(X+5)(3x-4)-3(x2+2)+4=0

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Solution for (X+5)(3x-4)-3(x2+2)+4=0 equation: 



(X+5)(3X-4)-3(X2+2)+4=0

We add all the numbers together, and all the variables

-3(+X^2+2)+(X+5)(3X-4)+4=0

We multiply parentheses

-3X^2+(X+5)(3X-4)-6+4=0

We multiply parentheses ..

-3X^2+(+3X^2-4X+15X-20)-6+4=0

We add all the numbers together, and all the variables

-3X^2+(+3X^2-4X+15X-20)-2=0

We get rid of parentheses

-3X^2+3X^2-4X+15X-20-2=0

We add all the numbers together, and all the variables

11X-22=0

We move all terms containing X to the left, all other terms to the right

11X=22

X=22/11

X=2

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