(2x-1)(x-4)=(x-1)(2x-7)

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Solution for (2x-1)(x-4)=(x-1)(2x-7) equation: 



(2x-1)(x-4)=(x-1)(2x-7)

We move all terms to the left:

(2x-1)(x-4)-((x-1)(2x-7))=0

We multiply parentheses ..

(+2x^2-8x-1x+4)-((x-1)(2x-7))=0



We calculate terms in parentheses: -((x-1)(2x-7)), so:

(x-1)(2x-7)

We multiply parentheses ..

(+2x^2-7x-2x+7)

We get rid of parentheses

2x^2-7x-2x+7

We add all the numbers together, and all the variables

2x^2-9x+7

Back to the equation:

-(2x^2-9x+7)



We get rid of parentheses

2x^2-2x^2-8x-1x+9x+4-7=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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