(X+2)/3=(3x-4)/2

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Solution for (X+2)/3=(3x-4)/2 equation: 



(X+2)/3=(3X-4)/2

We move all terms to the left:

(X+2)/3-((3X-4)/2)=0

We calculate fractions


X/()+(-((3X-4)*3)/()=0



We calculate terms in parentheses: +(-((3X-4)*3)/(), so:

-((3X-4)*3)/(

We multiply all the terms by the denominator


-((3X-4)*3)



We calculate terms in parentheses: -((3X-4)*3), so:

(3X-4)*3

We multiply parentheses

9X-12

Back to the equation:

-(9X-12)



We get rid of parentheses

-9X+12

Back to the equation:

+(-9X+12)



We get rid of parentheses

X/()-9X+12=0

We multiply all the terms by the denominator


X-9X*()+12*()=0

We add all the numbers together, and all the variables

X-9X*()=0

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