(X+2)+3=5(x-4)+4

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Solution for (X+2)+3=5(x-4)+4 equation: 



(X+2)+3=5(X-4)+4

We move all terms to the left:

(X+2)+3-(5(X-4)+4)=0

We get rid of parentheses

X-(5(X-4)+4)+2+3=0



We calculate terms in parentheses: -(5(X-4)+4), so:

5(X-4)+4

We multiply parentheses

5X-20+4

We add all the numbers together, and all the variables

5X-16

Back to the equation:

-(5X-16)



We add all the numbers together, and all the variables

X-(5X-16)+5=0

We get rid of parentheses

X-5X+16+5=0

We add all the numbers together, and all the variables

-4X+21=0

We move all terms containing X to the left, all other terms to the right

-4X=-21

X=-21/-4

X=5+1/4

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