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(X+2)(X+3)=(5+2)(5+3)
We move all terms to the left:
(X+2)(X+3)-((5+2)(5+3))=0
We add all the numbers together, and all the variables
(X+2)(X+3)-(78)=0
We add all the numbers together, and all the variables
(X+2)(X+3)-78=0
We multiply parentheses ..
(+X^2+3X+2X+6)-78=0
We get rid of parentheses
X^2+3X+2X+6-78=0
We add all the numbers together, and all the variables
X^2+5X-72=0
a = 1; b = 5; c = -72;
Δ = b2-4ac
Δ = 52-4·1·(-72)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{313}}{2*1}=\frac{-5-\sqrt{313}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{313}}{2*1}=\frac{-5+\sqrt{313}}{2} $
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