(X+14)+(3x-10)=160

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Solution for (X+14)+(3x-10)=160 equation: 



(X+14)+(3X-10)=160

We move all terms to the left:

(X+14)+(3X-10)-(160)=0

We get rid of parentheses

X+3X+14-10-160=0

We add all the numbers together, and all the variables

4X-156=0

We move all terms containing X to the left, all other terms to the right

4X=156

X=156/4

X=39

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