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(2x-1)=(5x)
We move all terms to the left:
(2x-1)-((5x))=0
determiningTheFunctionDomain (2x-1)-5x=0
We add all the numbers together, and all the variables
-5x+(2x-1)=0
We get rid of parentheses
-5x+2x-1=0
We add all the numbers together, and all the variables
-3x-1=0
We move all terms containing x to the left, all other terms to the right
-3x=1
x=1/-3
x=-1/3
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