(X+1)+(x+4)=(2-x)(x+2)

Solution for (X+1)+(x+4)=(2-x)(x+2) equation:

(X+1)+(X+4)=(2-X)(X+2)

We move all terms to the left:

(X+1)+(X+4)-((2-X)(X+2))=0

We add all the numbers together, and all the variables

(X+1)+(X+4)-((-1X+2)(X+2))=0

We get rid of parentheses

X+X-((-1X+2)(X+2))+1+4=0

We multiply parentheses ..

-((-1X^2-2X+2X+4))+X+X+1+4=0


We calculate terms in parentheses: -((-1X^2-2X+2X+4)), so:

(-1X^2-2X+2X+4)

We get rid of parentheses

-1X^2-2X+2X+4

We add all the numbers together, and all the variables

-1X^2+4

Back to the equation:

-(-1X^2+4)


We add all the numbers together, and all the variables

-(-1X^2+4)+2X+5=0

We get rid of parentheses

1X^2+2X-4+5=0

We add all the numbers together, and all the variables

X^2+2X+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{-2}{2}=-1$