(n/68)=(1/12)

Solution for (n/68)=(1/12) equation:

(n/68)=(1/12)

We move all terms to the left:

(n/68)-((1/12))=0

We add all the numbers together, and all the variables

(+n/68)-((+1/12))=0

We get rid of parentheses

n/68-((+1/12))=0

We calculate fractions


12n^2/()+()/()=0

We add all the numbers together, and all the variables

12n^2/()+1=0

We multiply all the terms by the denominator


12n^2+1*()=0

We add all the numbers together, and all the variables

12n^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{24}=0$