(X+1)+(x+2)+(x+3)=132

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Solution for (X+1)+(x+2)+(x+3)=132 equation: 



(X+1)+(X+2)+(X+3)=132

We move all terms to the left:

(X+1)+(X+2)+(X+3)-(132)=0

We get rid of parentheses

X+X+X+1+2+3-132=0

We add all the numbers together, and all the variables

3X-126=0

We move all terms containing X to the left, all other terms to the right

3X=126

X=126/3

X=42

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