(R+5)(r+1)=32

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Solution for (R+5)(r+1)=32 equation: 



(+5)(R+1)=32

We move all terms to the left:

(+5)(R+1)-(32)=0

We add all the numbers together, and all the variables

5(R+1)-32=0

We multiply parentheses

5R+5-32=0

We add all the numbers together, and all the variables

5R-27=0

We move all terms containing R to the left, all other terms to the right

5R=27

R=27/5

R=5+2/5

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