/3h-4(2/3h-3)=2/3h-6

Solution for /3h-4(2/3h-3)=2/3h-6 equation:

/3h-4(2/3h-3)=2/3h-6

We move all terms to the left:

/3h-4(2/3h-3)-(2/3h-6)=0


Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R



Domain of the equation: 3h-3)!=0

h∈R



Domain of the equation: 3h-6)!=0

h∈R


We multiply parentheses

/3h-8h-(2/3h-6)+12=0

We get rid of parentheses

/3h-8h-2/3h+6+12=0

We multiply all the terms by the denominator


-8h*3h+6*3h+12*3h-2+=0

We add all the numbers together, and all the variables

-8h*3h+6*3h+12*3h=0

Wy multiply elements

-24h^2+18h+36h=0

We add all the numbers together, and all the variables

-24h^2+54h=0

a = -24; b = 54; c = 0;
Δ = b2-4ac
Δ = 542-4·(-24)·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-54}{2*-24}=\frac{-108}{-48}
=2+1/4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+54}{2*-24}=\frac{0}{-48}
=0
$