(R+3)+0+(5r)=15

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Solution for (R+3)+0+(5r)=15 equation: 



(+3)+0+(5R)=15

We move all terms to the left:

(+3)+0+(5R)-(15)=0

determiningTheFunctionDomain
5R+0-15+(+3)=0

We add all the numbers together, and all the variables

5R+0-15+3=0

We add all the numbers together, and all the variables

5R-12=0

We move all terms containing R to the left, all other terms to the right

5R=12

R=12/5

R=2+2/5

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