2(r-3)+(r-3)=3

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Solution for 2(r-3)+(r-3)=3 equation: 



2(r-3)+(r-3)=3

We move all terms to the left:

2(r-3)+(r-3)-(3)=0

We multiply parentheses

2r+(r-3)-6-3=0

We get rid of parentheses

2r+r-3-6-3=0

We add all the numbers together, and all the variables

3r-12=0

We move all terms containing r to the left, all other terms to the right

3r=12

r=12/3

r=4

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