(C)5(y-1)-(y-2)=2(2y+3)-9

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Solution for (C)5(y-1)-(y-2)=2(2y+3)-9 equation: 



()5(C-1)-(C-2)=2(2C+3)-9

We move all terms to the left:

()5(C-1)-(C-2)-(2(2C+3)-9)=0

We get rid of parentheses

()5(C-1)-C-(2(2C+3)-9)+2=0



We calculate terms in parentheses: -(2(2C+3)-9), so:

2(2C+3)-9

We multiply parentheses

4C+6-9

We add all the numbers together, and all the variables

4C-3

Back to the equation:

-(4C-3)



We add all the numbers together, and all the variables

-1C+()5(C-1)-(4C-3)+2=0

We get rid of parentheses

-1C+()5(C-1)-4C+3+2=0

We add all the numbers together, and all the variables

-5C+()5(C-1)+5=0

We move all terms containing C to the left, all other terms to the right

-5C+()5(C-1)=-5

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