18=2(j+1)+6

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Solution for 18=2(j+1)+6 equation: 



18=2(j+1)+6

We move all terms to the left:

18-(2(j+1)+6)=0



We calculate terms in parentheses: -(2(j+1)+6), so:

2(j+1)+6

We multiply parentheses

2j+2+6

We add all the numbers together, and all the variables

2j+8

Back to the equation:

-(2j+8)



We get rid of parentheses

-2j-8+18=0

We add all the numbers together, and all the variables

-2j+10=0

We move all terms containing j to the left, all other terms to the right

-2j=-10

j=-10/-2

j=+5

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