(A+42)+(a+47)+(a+10)=180

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Solution for (A+42)+(a+47)+(a+10)=180 equation: 



(+42)+(A+47)+(A+10)=180

We move all terms to the left:

(+42)+(A+47)+(A+10)-(180)=0

determiningTheFunctionDomain
(A+47)+(A+10)-180+(+42)=0

We add all the numbers together, and all the variables

(A+47)+(A+10)-180+42=0

We add all the numbers together, and all the variables

(A+47)+(A+10)-138=0

We get rid of parentheses

A+A+47+10-138=0

We add all the numbers together, and all the variables

2A-81=0

We move all terms containing A to the left, all other terms to the right

2A=81

A=81/2

A=40+1/2

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