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(2x+14)(x+7)=180
We move all terms to the left:
(2x+14)(x+7)-(180)=0
We multiply parentheses ..
(+2x^2+14x+14x+98)-180=0
We get rid of parentheses
2x^2+14x+14x+98-180=0
We add all the numbers together, and all the variables
2x^2+28x-82=0
a = 2; b = 28; c = -82;
Δ = b2-4ac
Δ = 282-4·2·(-82)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-12\sqrt{10}}{2*2}=\frac{-28-12\sqrt{10}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+12\sqrt{10}}{2*2}=\frac{-28+12\sqrt{10}}{4} $
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