(9x-7)(7x-3)=180

Solution for (9x-7)(7x-3)=180 equation:

(9x-7)(7x-3)=180

We move all terms to the left:

(9x-7)(7x-3)-(180)=0

We multiply parentheses ..

(+63x^2-27x-49x+21)-180=0

We get rid of parentheses

63x^2-27x-49x+21-180=0

We add all the numbers together, and all the variables

63x^2-76x-159=0

a = 63; b = -76; c = -159;
Δ = b2-4ac
Δ = -762-4·63·(-159)
Δ = 45844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45844}=\sqrt{4*11461}=\sqrt{4}*\sqrt{11461}=2\sqrt{11461}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-2\sqrt{11461}}{2*63}=\frac{76-2\sqrt{11461}}{126}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+2\sqrt{11461}}{2*63}=\frac{76+2\sqrt{11461}}{126}
$