3(4x+3)=-3(3x-4)+5x

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Solution for 3(4x+3)=-3(3x-4)+5x equation:



3(4x+3)=-3(3x-4)+5x
We move all terms to the left:
3(4x+3)-(-3(3x-4)+5x)=0
We multiply parentheses
12x-(-3(3x-4)+5x)+9=0
We calculate terms in parentheses: -(-3(3x-4)+5x), so:
-3(3x-4)+5x
We add all the numbers together, and all the variables
5x-3(3x-4)
We multiply parentheses
5x-9x+12
We add all the numbers together, and all the variables
-4x+12
Back to the equation:
-(-4x+12)
We get rid of parentheses
12x+4x-12+9=0
We add all the numbers together, and all the variables
16x-3=0
We move all terms containing x to the left, all other terms to the right
16x=3
x=3/16
x=3/16

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