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(9x-6)=(3x+12)
We move all terms to the left:
(9x-6)-((3x+12))=0
We get rid of parentheses
9x-((3x+12))-6=0
We calculate terms in parentheses: -((3x+12)), so:We get rid of parentheses
(3x+12)
We get rid of parentheses
3x+12
Back to the equation:
-(3x+12)
9x-3x-12-6=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3
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