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(9x-6)(x-6)=0
We multiply parentheses ..
(+9x^2-54x-6x+36)=0
We get rid of parentheses
9x^2-54x-6x+36=0
We add all the numbers together, and all the variables
9x^2-60x+36=0
a = 9; b = -60; c = +36;
Δ = b2-4ac
Δ = -602-4·9·36
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-48}{2*9}=\frac{12}{18} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+48}{2*9}=\frac{108}{18} =6 $
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