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-15=-1/2(5b+5)
We move all terms to the left:
-15-(-1/2(5b+5))=0
Domain of the equation: 2(5b+5))!=0We multiply all the terms by the denominator
b∈R
-(-1-15*2(5b+5))=0
We calculate terms in parentheses: -(-1-15*2(5b+5)), so:We add all the numbers together, and all the variables
-1-15*2(5b+5)
determiningTheFunctionDomain -15*2(5b+5)-1
Wy multiply elements
-30b(5-1
Back to the equation:
-(-30b(5-1)
-(-30b4=0
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