(9x-4)+(8x+10)=(28x-2)

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Solution for (9x-4)+(8x+10)=(28x-2) equation: 



(9x-4)+(8x+10)=(28x-2)

We move all terms to the left:

(9x-4)+(8x+10)-((28x-2))=0

We get rid of parentheses

9x+8x-((28x-2))-4+10=0



We calculate terms in parentheses: -((28x-2)), so:

(28x-2)

We get rid of parentheses

28x-2

Back to the equation:

-(28x-2)



We add all the numbers together, and all the variables

17x-(28x-2)+6=0

We get rid of parentheses

17x-28x+2+6=0

We add all the numbers together, and all the variables

-11x+8=0

We move all terms containing x to the left, all other terms to the right

-11x=-8

x=-8/-11

x=8/11

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