3(x-4)=6(3x-2)

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Solution for 3(x-4)=6(3x-2) equation: 



3(x-4)=6(3x-2)

We move all terms to the left:

3(x-4)-(6(3x-2))=0

We multiply parentheses

3x-(6(3x-2))-12=0



We calculate terms in parentheses: -(6(3x-2)), so:

6(3x-2)

We multiply parentheses

18x-12

Back to the equation:

-(18x-12)



We get rid of parentheses

3x-18x+12-12=0

We add all the numbers together, and all the variables

-15x=0

x=0/-15

x=0

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