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(9x-3)=(19+5x+1)
We move all terms to the left:
(9x-3)-((19+5x+1))=0
We add all the numbers together, and all the variables
(9x-3)-((5x+20))=0
We get rid of parentheses
9x-((5x+20))-3=0
We calculate terms in parentheses: -((5x+20)), so:We get rid of parentheses
(5x+20)
We get rid of parentheses
5x+20
Back to the equation:
-(5x+20)
9x-5x-20-3=0
We add all the numbers together, and all the variables
4x-23=0
We move all terms containing x to the left, all other terms to the right
4x=23
x=23/4
x=5+3/4
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