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2(9x-3)=1/2(19+5x+1)2
We move all terms to the left:
2(9x-3)-(1/2(19+5x+1)2)=0
Domain of the equation: 2(19+5x+1)2)!=0We add all the numbers together, and all the variables
x∈R
2(9x-3)-(1/2(5x+20)2)=0
We multiply parentheses
18x-(1/2(5x+20)2)-6=0
We multiply all the terms by the denominator
18x*2(5x+20)2)-(1-6*2(5x+20)2)=0
Wy multiply elements
36x^2(5-12x(5=0
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