(9x-14)(5x+18)=0

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Solution for (9x-14)(5x+18)=0 equation:



(9x-14)(5x+18)=0
We multiply parentheses ..
(+45x^2+162x-70x-252)=0
We get rid of parentheses
45x^2+162x-70x-252=0
We add all the numbers together, and all the variables
45x^2+92x-252=0
a = 45; b = 92; c = -252;
Δ = b2-4ac
Δ = 922-4·45·(-252)
Δ = 53824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{53824}=232$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-232}{2*45}=\frac{-324}{90} =-3+3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+232}{2*45}=\frac{140}{90} =1+5/9 $

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