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(9x-13)(5x+23)=0
We multiply parentheses ..
(+45x^2+207x-65x-299)=0
We get rid of parentheses
45x^2+207x-65x-299=0
We add all the numbers together, and all the variables
45x^2+142x-299=0
a = 45; b = 142; c = -299;
Δ = b2-4ac
Δ = 1422-4·45·(-299)
Δ = 73984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{73984}=272$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(142)-272}{2*45}=\frac{-414}{90} =-4+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(142)+272}{2*45}=\frac{130}{90} =1+4/9 $
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