2u+3-2(-9u-5)=2(u-1)

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Solution for 2u+3-2(-9u-5)=2(u-1) equation: 



2u+3-2(-9u-5)=2(u-1)

We move all terms to the left:

2u+3-2(-9u-5)-(2(u-1))=0

We multiply parentheses

2u+18u-(2(u-1))+10+3=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We add all the numbers together, and all the variables

20u-(2u-2)+13=0

We get rid of parentheses

20u-2u+2+13=0

We add all the numbers together, and all the variables

18u+15=0

We move all terms containing u to the left, all other terms to the right

18u=-15

u=-15/18

u=-5/6

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