(9x+5)-(3x-7)=20-(4x-2)

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Solution for (9x+5)-(3x-7)=20-(4x-2) equation: 



(9x+5)-(3x-7)=20-(4x-2)

We move all terms to the left:

(9x+5)-(3x-7)-(20-(4x-2))=0

We get rid of parentheses

9x-3x-(20-(4x-2))+5+7=0



We calculate terms in parentheses: -(20-(4x-2)), so:

20-(4x-2)

determiningTheFunctionDomain
-(4x-2)+20

We get rid of parentheses

-4x+2+20

We add all the numbers together, and all the variables

-4x+22

Back to the equation:

-(-4x+22)



We add all the numbers together, and all the variables

6x-(-4x+22)+12=0

We get rid of parentheses

6x+4x-22+12=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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