-6a-40=8(1-3a)+6a

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Solution for -6a-40=8(1-3a)+6a equation: 



-6a-40=8(1-3a)+6a

We move all terms to the left:

-6a-40-(8(1-3a)+6a)=0

We add all the numbers together, and all the variables

-6a-(8(-3a+1)+6a)-40=0



We calculate terms in parentheses: -(8(-3a+1)+6a), so:

8(-3a+1)+6a

We add all the numbers together, and all the variables

6a+8(-3a+1)

We multiply parentheses

6a-24a+8

We add all the numbers together, and all the variables

-18a+8

Back to the equation:

-(-18a+8)



We get rid of parentheses

-6a+18a-8-40=0

We add all the numbers together, and all the variables

12a-48=0

We move all terms containing a to the left, all other terms to the right

12a=48

a=48/12

a=4

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