(9x+2)+11x2=10

Solution for (9x+2)+11x2=10 equation:

(9x+2)+11x^2=10

We move all terms to the left:

(9x+2)+11x^2-(10)=0

We get rid of parentheses

11x^2+9x+2-10=0

We add all the numbers together, and all the variables

11x^2+9x-8=0

a = 11; b = 9; c = -8;
Δ = b2-4ac
Δ = 92-4·11·(-8)
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{433}}{2*11}=\frac{-9-\sqrt{433}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{433}}{2*11}=\frac{-9+\sqrt{433}}{22}
$