(13.7)(10.4)=(1.47)(p2)

Solution for (13.7)(10.4)=(1.47)(p2) equation:

(13.7)(10.4)=(1.47)(p2)

We move all terms to the left:

(13.7)(10.4)-((1.47)(p2))=0

We add all the numbers together, and all the variables

-((1.47)p2)+142.48=0


We calculate terms in parentheses: -((1.47)p2), so:

(1.47)p2

We multiply parentheses

1.47p^2

Back to the equation:

-(1.47p^2)


We get rid of parentheses

-1.47p^2+142.48=0

a = -1.47; b = 0; c = +142.48;
Δ = b2-4ac
Δ = 02-4·(-1.47)·142.48
Δ = 837.7824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{837.7824}}{2*-1.47}=\frac{0-\sqrt{837.7824}}{-2.94}
=-\frac{\sqrt{}}{-2.94}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{837.7824}}{2*-1.47}=\frac{0+\sqrt{837.7824}}{-2.94}
=\frac{\sqrt{}}{-2.94}
$