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(3x-2)(5x+10)=0
We multiply parentheses ..
(+15x^2+30x-10x-20)=0
We get rid of parentheses
15x^2+30x-10x-20=0
We add all the numbers together, and all the variables
15x^2+20x-20=0
a = 15; b = 20; c = -20;
Δ = b2-4ac
Δ = 202-4·15·(-20)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*15}=\frac{-60}{30} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*15}=\frac{20}{30} =2/3 $
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