(9n+5)-(3n-7)=20-(4n-2)

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Solution for (9n+5)-(3n-7)=20-(4n-2) equation: 



(9n+5)-(3n-7)=20-(4n-2)

We move all terms to the left:

(9n+5)-(3n-7)-(20-(4n-2))=0

We get rid of parentheses

9n-3n-(20-(4n-2))+5+7=0



We calculate terms in parentheses: -(20-(4n-2)), so:

20-(4n-2)

determiningTheFunctionDomain
-(4n-2)+20

We get rid of parentheses

-4n+2+20

We add all the numbers together, and all the variables

-4n+22

Back to the equation:

-(-4n+22)



We add all the numbers together, and all the variables

6n-(-4n+22)+12=0

We get rid of parentheses

6n+4n-22+12=0

We add all the numbers together, and all the variables

10n-10=0

We move all terms containing n to the left, all other terms to the right

10n=10

n=10/10

n=1

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