(9k-3)/12=(3k+4)/8

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Solution for (9k-3)/12=(3k+4)/8 equation: 



(9k-3)/12=(3k+4)/8

We move all terms to the left:

(9k-3)/12-((3k+4)/8)=0

We calculate fractions


9k/()+(-((3k+4)*12)/()=0



We calculate terms in parentheses: +(-((3k+4)*12)/(), so:

-((3k+4)*12)/(

We multiply all the terms by the denominator


-((3k+4)*12)



We calculate terms in parentheses: -((3k+4)*12), so:

(3k+4)*12

We multiply parentheses

36k+48

Back to the equation:

-(36k+48)



We get rid of parentheses

-36k-48

Back to the equation:

+(-36k-48)



We get rid of parentheses

9k/()-36k-48=0

We multiply all the terms by the denominator


9k-36k*()-48*()=0

We add all the numbers together, and all the variables

9k-36k*()=0

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