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4/5x+1=1/5=1/5x
We move all terms to the left:
4/5x+1-(1/5)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4/5x+1-(+1/5)=0
We get rid of parentheses
4/5x+1-1/5=0
We calculate fractions
1!=0
There is no solution for this equation
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