(99-4z)-11+(4z+2)=90

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Solution for (99-4z)-11+(4z+2)=90 equation: 



(99-4z)-11+(4z+2)=90

We move all terms to the left:

(99-4z)-11+(4z+2)-(90)=0

We add all the numbers together, and all the variables

(-4z+99)+(4z+2)-11-90=0

We add all the numbers together, and all the variables

(-4z+99)+(4z+2)-101=0

We get rid of parentheses

-4z+4z+99+2-101=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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