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(9/5)x+32=x
We move all terms to the left:
(9/5)x+32-(x)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+9/5)x-x+32=0
We add all the numbers together, and all the variables
-1x+(+9/5)x+32=0
We multiply parentheses
9x^2-1x+32=0
a = 9; b = -1; c = +32;
Δ = b2-4ac
Δ = -12-4·9·32
Δ = -1151
Delta is less than zero, so there is no solution for the equation
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