(9-y)(5y+7)=0

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Solution for (9-y)(5y+7)=0 equation:



(9-y)(5y+7)=0
We add all the numbers together, and all the variables
(-1y+9)(5y+7)=0
We multiply parentheses ..
(-5y^2-7y+45y+63)=0
We get rid of parentheses
-5y^2-7y+45y+63=0
We add all the numbers together, and all the variables
-5y^2+38y+63=0
a = -5; b = 38; c = +63;
Δ = b2-4ac
Δ = 382-4·(-5)·63
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-52}{2*-5}=\frac{-90}{-10} =+9 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+52}{2*-5}=\frac{14}{-10} =-1+2/5 $

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