-2x+4(3-x)=-x+17(x-2)

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Solution for -2x+4(3-x)=-x+17(x-2) equation: 



-2x+4(3-x)=-x+17(x-2)

We move all terms to the left:

-2x+4(3-x)-(-x+17(x-2))=0

We add all the numbers together, and all the variables

-2x+4(-1x+3)-(-x+17(x-2))=0

We multiply parentheses

-2x-4x-(-x+17(x-2))+12=0



We calculate terms in parentheses: -(-x+17(x-2)), so:

-x+17(x-2)

We add all the numbers together, and all the variables

-1x+17(x-2)

We multiply parentheses

-1x+17x-34

We add all the numbers together, and all the variables

16x-34

Back to the equation:

-(16x-34)



We add all the numbers together, and all the variables

-6x-(16x-34)+12=0

We get rid of parentheses

-6x-16x+34+12=0

We add all the numbers together, and all the variables

-22x+46=0

We move all terms containing x to the left, all other terms to the right

-22x=-46

x=-46/-22

x=2+1/11

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