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(9-x)/3=2x+1
We move all terms to the left:
(9-x)/3-(2x+1)=0
We add all the numbers together, and all the variables
(-1x+9)/3-(2x+1)=0
We get rid of parentheses
(-1x+9)/3-2x-1=0
We multiply all the terms by the denominator
(-1x+9)-2x*3-1*3=0
We add all the numbers together, and all the variables
(-1x+9)-2x*3-3=0
Wy multiply elements
(-1x+9)-6x-3=0
We get rid of parentheses
-1x-6x+9-3=0
We add all the numbers together, and all the variables
-7x+6=0
We move all terms containing x to the left, all other terms to the right
-7x=-6
x=-6/-7
x=6/7
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