(9-3(2z+1))/(3)+8z=0

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Solution for (9-3(2z+1))/(3)+8z=0 equation: 



(9-3(2z+1))/(3)+8z=0

We add all the numbers together, and all the variables

8z+(9-3(2z+1))/3=0

We multiply all the terms by the denominator


8z*3+(9-3(2z+1))=0



We calculate terms in parentheses: +(9-3(2z+1)), so:

9-3(2z+1)

determiningTheFunctionDomain
-3(2z+1)+9

We multiply parentheses

-6z-3+9

We add all the numbers together, and all the variables

-6z+6

Back to the equation:

+(-6z+6)



Wy multiply elements

24z+(-6z+6)=0

We get rid of parentheses

24z-6z+6=0

We add all the numbers together, and all the variables

18z+6=0

We move all terms containing z to the left, all other terms to the right

18z=-6

z=-6/18

z=-1/3

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