(2z/z-2)-(3/z+5)=1

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Solution for (2z/z-2)-(3/z+5)=1 equation: 



(2z/z-2)-(3/z+5)=1

We move all terms to the left:

(2z/z-2)-(3/z+5)-(1)=0



Domain of the equation: z-2)!=0

z∈R





Domain of the equation: z+5)!=0

z∈R



We get rid of parentheses

2z/z-3/z-2-5-1=0

We multiply all the terms by the denominator


2z-2*z-5*z-1*z-3=0

We add all the numbers together, and all the variables

-6z-3=0

We move all terms containing z to the left, all other terms to the right

-6z=3

z=3/-6

z=-1/2

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