(9+8i)(9+8i)=0

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Solution for (9+8i)(9+8i)=0 equation:



(9+8i)(9+8i)=0
We add all the numbers together, and all the variables
(8i+9)(8i+9)=0
We multiply parentheses ..
(+64i^2+72i+72i+81)=0
We get rid of parentheses
64i^2+72i+72i+81=0
We add all the numbers together, and all the variables
64i^2+144i+81=0
a = 64; b = 144; c = +81;
Δ = b2-4ac
Δ = 1442-4·64·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-144}{128}=-1+1/8$

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