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(10x-50)(x+12)=0
We multiply parentheses ..
(+10x^2+120x-50x-600)=0
We get rid of parentheses
10x^2+120x-50x-600=0
We add all the numbers together, and all the variables
10x^2+70x-600=0
a = 10; b = 70; c = -600;
Δ = b2-4ac
Δ = 702-4·10·(-600)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28900}=170$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-170}{2*10}=\frac{-240}{20} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+170}{2*10}=\frac{100}{20} =5 $
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