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(9+2i)(3-5i)-(9+i)(3-5i)=15+9i
We move all terms to the left:
(9+2i)(3-5i)-(9+i)(3-5i)-(15+9i)=0
We add all the numbers together, and all the variables
(2i+9)(-5i+3)-(i+9)(-5i+3)-(9i+15)=0
We get rid of parentheses
(2i+9)(-5i+3)-(i+9)(-5i+3)-9i-15=0
We multiply parentheses ..
(-10i^2+6i-45i+27)-(i+9)(-5i+3)-9i-15=0
We add all the numbers together, and all the variables
(-10i^2+6i-45i+27)-9i-(i+9)(-5i+3)-15=0
We get rid of parentheses
-10i^2+6i-45i-9i-(i+9)(-5i+3)+27-15=0
We multiply parentheses ..
-10i^2-(-5i^2+3i-45i+27)+6i-45i-9i+27-15=0
We add all the numbers together, and all the variables
-10i^2-(-5i^2+3i-45i+27)-48i+12=0
We get rid of parentheses
-10i^2+5i^2-3i+45i-48i-27+12=0
We add all the numbers together, and all the variables
-5i^2-6i-15=0
a = -5; b = -6; c = -15;
Δ = b2-4ac
Δ = -62-4·(-5)·(-15)
Δ = -264
Delta is less than zero, so there is no solution for the equation
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