If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6n^2+48n+96=0
a = 6; b = 48; c = +96;
Δ = b2-4ac
Δ = 482-4·6·96
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$n=\frac{-b}{2a}=\frac{-48}{12}=-4$
| -2=3/5r-5 | | x+5*2-6/2=8 | | x^2-x+.26=0 | | 17.94=3.9(g-15.5)+8.97 | | -9y=-10y+20 | | -19-11q=-13q+13 | | 15(x)=3 | | -12(x-9)=-6(8-3x | | 15(x)=2 | | 164=4+8(-3p-1) | | 19v-16v=+3=15 | | 15x2(x)=3 | | 5x+5=-10-9x | | -4+2v=4 | | -11-10p=19-12p | | -42v=4 | | 3=-3+y/3 | | 13v-4=14v | | 2x/3-5=21 | | 20-14b=-9b | | 4(2r+6)=7r+32 | | -7–13c=15c–63 | | 6g-5g=4 | | 42x+18=-24+97x | | 4.8b+2.3=11.9 | | 4x^-x-3=0 | | 19x+27=24 | | 15=2y-5= | | 1/8•e=7 | | 2b+2b-1=15 | | 510=x/2+400 | | 7(x)+6=21 |