(8y-7)=(3y+13)

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Solution for (8y-7)=(3y+13) equation: 



(8y-7)=(3y+13)

We move all terms to the left:

(8y-7)-((3y+13))=0

We get rid of parentheses

8y-((3y+13))-7=0



We calculate terms in parentheses: -((3y+13)), so:

(3y+13)

We get rid of parentheses

3y+13

Back to the equation:

-(3y+13)



We get rid of parentheses

8y-3y-13-7=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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